Hey guys I attached a pic of question 20 in the 30 minute exams. Was hoping someone could clarify why the net force is in the given direction. Thanks.
EK 30 min exam question
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Question stem indicates a component of it's acceleration is in the x-direction following the application of a 3rd force. The sum of the forces along the x-axis is negative in this case. Recall that Ftot = Fa + ... + Fn = ma.
While the RBC may still be traveling in the +x direction, it is accelerating in the opposite direction (i.e. decelerating in the +x direction).
In response to @NITRAS , The question stem does not indicate anything as to the nature of the y-component of acceleration after the 3rd force has been applied. The y-direction force components do not necessarily cancel out, but we do know that the net force could be in quadrants 2,3, or along the x-axis because each would have a component of force in the -x direction.
Question stem indicates a component of it's acceleration is in the x-direction following the application of a 3rd force. The sum of the forces along the x-axis is negative in this case. Recall that Ftot = Fa + ... + Fn = ma.
While the RBC may still be traveling in the +x direction, it is accelerating in the opposite direction (i.e. decelerating in the +x direction).
In response to @NITRAS , The question stem does not indicate anything as to the nature of the y-component of acceleration after the 3rd force has been applied. The y-direction force components do not necessarily cancel out, but we do know that the net force could be in quadrants 2,3, or along the x-axis because each would have a component of force in the -x direction.
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The cell is accelerating in the x plane, therefore the y components of the two forces are a net zero. The net force is +x.
The addition of a force in the -x direction should accelerate the cell in the -x direction.
The addition of a force in the -x direction should accelerate the cell in the -x direction.